| Practice Problem 5-1 (a) |
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Given: A solid shaft with two gears, A and B, is driven by a motor. Gears A and B apply torques to the shaft of TA = 250 in-lb and TB = 300 in-lb. The shaft has the following dimensions: diameter, D = 0.5 in.; L1 = 6 in.; and L2 = 10 in. The Shear Modulus of the shaft is G = 10 Msi. Req'd: What is the Polar Moment of Inertia of the shaft, J [in4]? |
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Solution: The polar moment of inertia of a solid shaft is given by: J = pR4/2 = p(0.25 in)4/2 = 0.00614 in4 |
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