Practice Problem 2-4 (a) |
Given: The truss system at right is subjected to a load which is redistributed along the top members resulting in a force of W = 200 lb at each of the five joints A, H, G, F, and E. Let q = 30°. Req'd: |
Solution: Due to the symmetry of the system we can say that RA = RE, therefore summing the forces in the vertical direction gives: 2(RA) = 5(W) RA = 5/2(W) = 5/2(200 lb) = 500 lb |